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36=(x+7)(x+2)
We move all terms to the left:
36-((x+7)(x+2))=0
We multiply parentheses ..
-((+x^2+2x+7x+14))+36=0
We calculate terms in parentheses: -((+x^2+2x+7x+14)), so:We get rid of parentheses
(+x^2+2x+7x+14)
We get rid of parentheses
x^2+2x+7x+14
We add all the numbers together, and all the variables
x^2+9x+14
Back to the equation:
-(x^2+9x+14)
-x^2-9x-14+36=0
We add all the numbers together, and all the variables
-1x^2-9x+22=0
a = -1; b = -9; c = +22;
Δ = b2-4ac
Δ = -92-4·(-1)·22
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-13}{2*-1}=\frac{-4}{-2} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+13}{2*-1}=\frac{22}{-2} =-11 $
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