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x^2-168x-1120=0
a = 1; b = -168; c = -1120;
Δ = b2-4ac
Δ = -1682-4·1·(-1120)
Δ = 32704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32704}=\sqrt{64*511}=\sqrt{64}*\sqrt{511}=8\sqrt{511}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-168)-8\sqrt{511}}{2*1}=\frac{168-8\sqrt{511}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-168)+8\sqrt{511}}{2*1}=\frac{168+8\sqrt{511}}{2} $
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