(x)=(x+9)(x+4)

Solution for (x)=(x+9)(x+4) equation:

(x)=(x+9)(x+4)

We move all terms to the left:

(x)-((x+9)(x+4))=0

We multiply parentheses ..

-((+x^2+4x+9x+36))+x=0


We calculate terms in parentheses: -((+x^2+4x+9x+36)), so:

(+x^2+4x+9x+36)

We get rid of parentheses

x^2+4x+9x+36

We add all the numbers together, and all the variables

x^2+13x+36

Back to the equation:

-(x^2+13x+36)


We add all the numbers together, and all the variables

x-(x^2+13x+36)=0

We get rid of parentheses

-x^2+x-13x-36=0

We add all the numbers together, and all the variables

-1x^2-12x-36=0

a = -1; b = -12; c = -36;
Δ = b2-4ac
Δ = -122-4·(-1)·(-36)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{-2}=-6$