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w(3w-5)=84
We move all terms to the left:
w(3w-5)-(84)=0
We multiply parentheses
3w^2-5w-84=0
a = 3; b = -5; c = -84;
Δ = b2-4ac
Δ = -52-4·3·(-84)
Δ = 1033
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{1033}}{2*3}=\frac{5-\sqrt{1033}}{6} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{1033}}{2*3}=\frac{5+\sqrt{1033}}{6} $
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