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3(x+5)-5=2(x-2)+4x
We move all terms to the left:
3(x+5)-5-(2(x-2)+4x)=0
We multiply parentheses
3x-(2(x-2)+4x)+15-5=0
We calculate terms in parentheses: -(2(x-2)+4x), so:We add all the numbers together, and all the variables
2(x-2)+4x
We add all the numbers together, and all the variables
4x+2(x-2)
We multiply parentheses
4x+2x-4
We add all the numbers together, and all the variables
6x-4
Back to the equation:
-(6x-4)
3x-(6x-4)+10=0
We get rid of parentheses
3x-6x+4+10=0
We add all the numbers together, and all the variables
-3x+14=0
We move all terms containing x to the left, all other terms to the right
-3x=-14
x=-14/-3
x=4+2/3
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