v+5-2(-3v-5)=3(v+1)

Solution for v+5-2(-3v-5)=3(v+1) equation:

v+5-2(-3v-5)=3(v+1)

We move all terms to the left:

v+5-2(-3v-5)-(3(v+1))=0

We multiply parentheses

v+6v-(3(v+1))+10+5=0


We calculate terms in parentheses: -(3(v+1)), so:

3(v+1)

We multiply parentheses

3v+3

Back to the equation:

-(3v+3)


We add all the numbers together, and all the variables

7v-(3v+3)+15=0

We get rid of parentheses

7v-3v-3+15=0

We add all the numbers together, and all the variables

4v+12=0

We move all terms containing v to the left, all other terms to the right

4v=-12

v=-12/4

v=-3