6x-2(x+2)=2-3(x+4)

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Solution for 6x-2(x+2)=2-3(x+4) equation: 



6x-2(x+2)=2-3(x+4)

We move all terms to the left:

6x-2(x+2)-(2-3(x+4))=0

We multiply parentheses

6x-2x-(2-3(x+4))-4=0



We calculate terms in parentheses: -(2-3(x+4)), so:

2-3(x+4)

determiningTheFunctionDomain
-3(x+4)+2

We multiply parentheses

-3x-12+2

We add all the numbers together, and all the variables

-3x-10

Back to the equation:

-(-3x-10)



We add all the numbers together, and all the variables

4x-(-3x-10)-4=0

We get rid of parentheses

4x+3x+10-4=0

We add all the numbers together, and all the variables

7x+6=0

We move all terms containing x to the left, all other terms to the right

7x=-6

x=-6/7

x=-6/7

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