t/9+2(t/28+4)=10

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Solution for t/9+2(t/28+4)=10 equation: 



t/9+2(t/28+4)=10

We move all terms to the left:

t/9+2(t/28+4)-(10)=0

We multiply parentheses

t/9+2t+8-10=0

We multiply all the terms by the denominator


t+2t*9+8*9-10*9=0

We add all the numbers together, and all the variables

t+2t*9-18=0

Wy multiply elements

t+18t-18=0

We add all the numbers together, and all the variables

19t-18=0

We move all terms containing t to the left, all other terms to the right

19t=18

t=18/19

t=18/19

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