3(m+2)5m=58

Solution for 3(m+2)5m=58 equation:

3(m+2)5m=58

We move all terms to the left:

3(m+2)5m-(58)=0

We multiply parentheses

15m^2+30m-58=0

a = 15; b = 30; c = -58;
Δ = b2-4ac
Δ = 302-4·15·(-58)
Δ = 4380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4380}=\sqrt{4*1095}=\sqrt{4}*\sqrt{1095}=2\sqrt{1095}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{1095}}{2*15}=\frac{-30-2\sqrt{1095}}{30}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{1095}}{2*15}=\frac{-30+2\sqrt{1095}}{30}
$