t/4+5t/3=7/2(t-1)

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Solution for t/4+5t/3=7/2(t-1) equation: 



t/4+5t/3=7/2(t-1)

We move all terms to the left:

t/4+5t/3-(7/2(t-1))=0



Domain of the equation: 2(t-1))!=0

t∈R



We calculate fractions


12t^2/48t+80t^2/48t+()/48t=0

We multiply all the terms by the denominator


12t^2+80t^2+()=0

We add all the numbers together, and all the variables

92t^2=0

a = 92; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·92·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{184}=0$

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