3(6+7y)+21(1-5y)=42

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Solution for 3(6+7y)+21(1-5y)=42 equation: 



3(6+7y)+21(1-5y)=42

We move all terms to the left:

3(6+7y)+21(1-5y)-(42)=0

We add all the numbers together, and all the variables

3(7y+6)+21(-5y+1)-42=0

We multiply parentheses

21y-105y+18+21-42=0

We add all the numbers together, and all the variables

-84y-3=0

We move all terms containing y to the left, all other terms to the right

-84y=3

y=3/-84

y=-1/28

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