t/2=(t+1)/5

Solution for t/2=(t+1)/5 equation:

t/2=(t+1)/5

We move all terms to the left:

t/2-((t+1)/5)=0

We calculate fractions


5t^2/()+(-((t+1)*2)/()=0


We calculate terms in parentheses: +(-((t+1)*2)/(), so:

-((t+1)*2)/(

We multiply all the terms by the denominator


-((t+1)*2)


We calculate terms in parentheses: -((t+1)*2), so:

(t+1)*2

We multiply parentheses

2t+2

Back to the equation:

-(2t+2)


We get rid of parentheses

-2t-2

Back to the equation:

+(-2t-2)


We get rid of parentheses

5t^2/()-2t-2=0

We multiply all the terms by the denominator


5t^2-2t*()-2*()=0

We add all the numbers together, and all the variables

5t^2-2t*()=0