1/2c+4=1/8c+88

Solution for 1/2c+4=1/8c+88 equation:

1/2c+4=1/8c+88

We move all terms to the left:

1/2c+4-(1/8c+88)=0


Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R



Domain of the equation: 8c+88)!=0

c∈R


We get rid of parentheses

1/2c-1/8c-88+4=0

We calculate fractions


8c/16c^2+(-2c)/16c^2-88+4=0

We add all the numbers together, and all the variables

8c/16c^2+(-2c)/16c^2-84=0

We multiply all the terms by the denominator


8c+(-2c)-84*16c^2=0

Wy multiply elements

-1344c^2+8c+(-2c)=0

We get rid of parentheses

-1344c^2+8c-2c=0

We add all the numbers together, and all the variables

-1344c^2+6c=0

a = -1344; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-1344)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-1344}=\frac{-12}{-2688}
=1/224
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-1344}=\frac{0}{-2688}
=0
$