t+18-1t=3(2t-2)

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Solution for t+18-1t=3(2t-2) equation: 



t+18-1t=3(2t-2)

We move all terms to the left:

t+18-1t-(3(2t-2))=0

We add all the numbers together, and all the variables

-(3(2t-2))+18=0



We calculate terms in parentheses: -(3(2t-2)), so:

3(2t-2)

We multiply parentheses

6t-6

Back to the equation:

-(6t-6)



We get rid of parentheses

-6t+6+18=0

We add all the numbers together, and all the variables

-6t+24=0

We move all terms containing t to the left, all other terms to the right

-6t=-24

t=-24/-6

t=+4

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