-9=3(j+2)+-3

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Solution for -9=3(j+2)+-3 equation: 



-9=3(j+2)+-3

We move all terms to the left:

-9-(3(j+2)+-3)=0

We use the square of the difference formula

-(3(j+2)-3)-9=0



We calculate terms in parentheses: -(3(j+2)-3), so:

3(j+2)-3

We multiply parentheses

3j+6-3

We add all the numbers together, and all the variables

3j+3

Back to the equation:

-(3j+3)



We get rid of parentheses

-3j-3-9=0

We add all the numbers together, and all the variables

-3j-12=0

We move all terms containing j to the left, all other terms to the right

-3j=12

j=12/-3

j=-4

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