s+2s+3=(4s-5)

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Solution for s+2s+3=(4s-5) equation: 



s+2s+3=(4s-5)

We move all terms to the left:

s+2s+3-((4s-5))=0

We add all the numbers together, and all the variables

3s-((4s-5))+3=0



We calculate terms in parentheses: -((4s-5)), so:

(4s-5)

We get rid of parentheses

4s-5

Back to the equation:

-(4s-5)



We get rid of parentheses

3s-4s+5+3=0

We add all the numbers together, and all the variables

-1s+8=0

We move all terms containing s to the left, all other terms to the right

-s=-8

s=-8/-1

s=+8

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