s+2s+3+(4s-5)=148

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Solution for s+2s+3+(4s-5)=148 equation: 



s+2s+3+(4s-5)=148

We move all terms to the left:

s+2s+3+(4s-5)-(148)=0

We add all the numbers together, and all the variables

3s+(4s-5)-145=0

We get rid of parentheses

3s+4s-5-145=0

We add all the numbers together, and all the variables

7s-150=0

We move all terms containing s to the left, all other terms to the right

7s=150

s=150/7

s=21+3/7

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