s+(3+s)+2s=17

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Solution for s+(3+s)+2s=17 equation: 



s+(3+s)+2s=17

We move all terms to the left:

s+(3+s)+2s-(17)=0

We add all the numbers together, and all the variables

s+(s+3)+2s-17=0

We add all the numbers together, and all the variables

3s+(s+3)-17=0

We get rid of parentheses

3s+s+3-17=0

We add all the numbers together, and all the variables

4s-14=0

We move all terms containing s to the left, all other terms to the right

4s=14

s=14/4

s=3+1/2

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