32+7z=8(6z-5)

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Solution for 32+7z=8(6z-5) equation:



32+7z=8(6z-5)
We move all terms to the left:
32+7z-(8(6z-5))=0
We calculate terms in parentheses: -(8(6z-5)), so:
8(6z-5)
We multiply parentheses
48z-40
Back to the equation:
-(48z-40)
We get rid of parentheses
7z-48z+40+32=0
We add all the numbers together, and all the variables
-41z+72=0
We move all terms containing z to the left, all other terms to the right
-41z=-72
z=-72/-41
z=1+31/41

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