r2=64r=

Solution for r2=64r= equation:

r2=64r=

We move all terms to the left:

r2-(64r)=0

We add all the numbers together, and all the variables

r^2-64r=0

a = 1; b = -64; c = 0;
Δ = b2-4ac
Δ = -642-4·1·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*1}=\frac{0}{2}
=0
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*1}=\frac{128}{2}
=64
$