r(8+3)=10(r-4)+8

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Solution for r(8+3)=10(r-4)+8 equation: 



r(8+3)=10(r-4)+8

We move all terms to the left:

r(8+3)-(10(r-4)+8)=0

We add all the numbers together, and all the variables

r11-(10(r-4)+8)=0

We add all the numbers together, and all the variables

r^11-(10(r-4)+8)=0



We calculate terms in parentheses: -(10(r-4)+8), so:

10(r-4)+8

We multiply parentheses

10r-40+8

We add all the numbers together, and all the variables

10r-32

Back to the equation:

-(10r-32)



We do not support erpression: r^11

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