p(1-p)=0,06

Solution for p(1-p)=0,06 equation:

p(1-p)=0.06

We move all terms to the left:

p(1-p)-(0.06)=0

We add all the numbers together, and all the variables

p(-1p+1)-(0.06)=0

We add all the numbers together, and all the variables

p(-1p+1)-0.06=0

We multiply parentheses

-1p^2+p-0.06=0

a = -1; b = 1; c = -0.06;
Δ = b2-4ac
Δ = 12-4·(-1)·(-0.06)
Δ = 0.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{0.76}}{2*-1}=\frac{-1-\sqrt{0.76}}{-2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{0.76}}{2*-1}=\frac{-1+\sqrt{0.76}}{-2}
$