x=-1.75x2+10

Solution for x=-1.75x2+10 equation:

x=-1.75x^2+10

We move all terms to the left:

x-(-1.75x^2+10)=0

We get rid of parentheses

1.75x^2+x-10=0

a = 1.75; b = 1; c = -10;
Δ = b2-4ac
Δ = 12-4·1.75·(-10)
Δ = 71
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{71}}{2*1.75}=\frac{-1-\sqrt{71}}{3.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{71}}{2*1.75}=\frac{-1+\sqrt{71}}{3.5}
$