n=2(4-3n)=n+12

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Solution for n=2(4-3n)=n+12 equation: 



n=2(4-3n)=n+12

We move all terms to the left:

n-(2(4-3n))=0

We add all the numbers together, and all the variables

n-(2(-3n+4))=0



We calculate terms in parentheses: -(2(-3n+4)), so:

2(-3n+4)

We multiply parentheses

-6n+8

Back to the equation:

-(-6n+8)



We get rid of parentheses

n+6n-8=0

We add all the numbers together, and all the variables

7n-8=0

We move all terms containing n to the left, all other terms to the right

7n=8

n=8/7

n=1+1/7

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