c=2.5(8c+5/2)=3c+2

Solution for c=2.5(8c+5/2)=3c+2 equation:

c=2.5(8c+5/2)=3c+2

We move all terms to the left:

c-(2.5(8c+5/2))=0

We add all the numbers together, and all the variables

c-(2.5(+8c+5/2))=0

We multiply all the terms by the denominator


c*2))-(2.5(+8c+5=0

We add all the numbers together, and all the variables

8c+c*2))-(2.5(+5=0

Wy multiply elements

2c^2+8c+5=0

a = 2; b = 8; c = +5;
Δ = b2-4ac
Δ = 82-4·2·5
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{6}}{2*2}=\frac{-8-2\sqrt{6}}{4}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{6}}{2*2}=\frac{-8+2\sqrt{6}}{4}
$