n=(n+2)=2(n+1)

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Solution for n=(n+2)=2(n+1) equation: 



n=(n+2)=2(n+1)

We move all terms to the left:

n-((n+2))=0



We calculate terms in parentheses: -((n+2)), so:

(n+2)

We get rid of parentheses

n+2

Back to the equation:

-(n+2)



We get rid of parentheses

n-n-2=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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