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3x+4(x-8)=3(2x+3)
We move all terms to the left:
3x+4(x-8)-(3(2x+3))=0
We multiply parentheses
3x+4x-(3(2x+3))-32=0
We calculate terms in parentheses: -(3(2x+3)), so:We add all the numbers together, and all the variables
3(2x+3)
We multiply parentheses
6x+9
Back to the equation:
-(6x+9)
7x-(6x+9)-32=0
We get rid of parentheses
7x-6x-9-32=0
We add all the numbers together, and all the variables
x-41=0
We move all terms containing x to the left, all other terms to the right
x=41
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