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n2-20n+84=0
We add all the numbers together, and all the variables
n^2-20n+84=0
a = 1; b = -20; c = +84;
Δ = b2-4ac
Δ = -202-4·1·84
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-8}{2*1}=\frac{12}{2} =6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+8}{2*1}=\frac{28}{2} =14 $
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