5(b+3)=-(-8+2b)

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Solution for 5(b+3)=-(-8+2b) equation:



5(b+3)=-(-8+2b)
We move all terms to the left:
5(b+3)-(-(-8+2b))=0
We add all the numbers together, and all the variables
5(b+3)-(-(2b-8))=0
We multiply parentheses
5b-(-(2b-8))+15=0
We calculate terms in parentheses: -(-(2b-8)), so:
-(2b-8)
We get rid of parentheses
-2b+8
Back to the equation:
-(-2b+8)
We get rid of parentheses
5b+2b-8+15=0
We add all the numbers together, and all the variables
7b+7=0
We move all terms containing b to the left, all other terms to the right
7b=-7
b=-7/7
b=-1

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