n2+12n-13=0

Solution for n2+12n-13=0 equation:

n2+12n-13=0

We add all the numbers together, and all the variables

n^2+12n-13=0

a = 1; b = 12; c = -13;
Δ = b2-4ac
Δ = 122-4·1·(-13)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-14}{2*1}=\frac{-26}{2}
=-13
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+14}{2*1}=\frac{2}{2}
=1
$