(3y-6/2y)=(17/3)

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Solution for (3y-6/2y)=(17/3) equation: 



(3y-6/2y)=(17/3)

We move all terms to the left:

(3y-6/2y)-((17/3))=0



Domain of the equation: 2y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+3y-6/2y)-((+17/3))=0

We get rid of parentheses

3y-6/2y-((+17/3))=0

We calculate fractions


3y+()/6y^2+(-((+17*2y)/6y^2=0

We multiply all the terms by the denominator


3y*6y^2+(-((+17*2y)+()=0



We calculate terms in parentheses: +(-((+17*2y)+(), so:

-((+17*2y)+(



Wy multiply elements

18y^3+(-((+17*2y)+()=0



We calculate terms in parentheses: +(-((+17*2y)+(), so:

-((+17*2y)+(



We do not support eypression: y^3

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