n+4n+3(n+50)+2n-100+5(n+4n)+4(2n-100)=3950

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Solution for n+4n+3(n+50)+2n-100+5(n+4n)+4(2n-100)=3950 equation: 



n+4n+3(n+50)+2n-100+5(n+4n)+4(2n-100)=3950

We move all terms to the left:

n+4n+3(n+50)+2n-100+5(n+4n)+4(2n-100)-(3950)=0

We add all the numbers together, and all the variables

n+4n+3(n+50)+2n+5(+5n)+4(2n-100)-100-3950=0

We add all the numbers together, and all the variables

7n+3(n+50)+5(+5n)+4(2n-100)-4050=0

We multiply parentheses

7n+3n+25n+8n+150-400-4050=0

We add all the numbers together, and all the variables

43n-4300=0

We move all terms containing n to the left, all other terms to the right

43n=4300

n=4300/43

n=100

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