n+4+7=-6(1+2n)-3(5-3n)

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Solution for n+4+7=-6(1+2n)-3(5-3n) equation: 



n+4+7=-6(1+2n)-3(5-3n)

We move all terms to the left:

n+4+7-(-6(1+2n)-3(5-3n))=0

We add all the numbers together, and all the variables

n-(-6(2n+1)-3(-3n+5))+4+7=0

We add all the numbers together, and all the variables

n-(-6(2n+1)-3(-3n+5))+11=0



We calculate terms in parentheses: -(-6(2n+1)-3(-3n+5)), so:

-6(2n+1)-3(-3n+5)

We multiply parentheses

-12n+9n-6-15

We add all the numbers together, and all the variables

-3n-21

Back to the equation:

-(-3n-21)



We get rid of parentheses

n+3n+21+11=0

We add all the numbers together, and all the variables

4n+32=0

We move all terms containing n to the left, all other terms to the right

4n=-32

n=-32/4

n=-8

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