8u+3-3(-3u-3)=2(u-3)

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Solution for 8u+3-3(-3u-3)=2(u-3) equation: 



8u+3-3(-3u-3)=2(u-3)

We move all terms to the left:

8u+3-3(-3u-3)-(2(u-3))=0

We multiply parentheses

8u+9u-(2(u-3))+9+3=0



We calculate terms in parentheses: -(2(u-3)), so:

2(u-3)

We multiply parentheses

2u-6

Back to the equation:

-(2u-6)



We add all the numbers together, and all the variables

17u-(2u-6)+12=0

We get rid of parentheses

17u-2u+6+12=0

We add all the numbers together, and all the variables

15u+18=0

We move all terms containing u to the left, all other terms to the right

15u=-18

u=-18/15

u=-1+1/5

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