n+3n-2=2(2n+1)+5n+7

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Solution for n+3n-2=2(2n+1)+5n+7 equation: 



n+3n-2=2(2n+1)+5n+7

We move all terms to the left:

n+3n-2-(2(2n+1)+5n+7)=0

We add all the numbers together, and all the variables

4n-(2(2n+1)+5n+7)-2=0



We calculate terms in parentheses: -(2(2n+1)+5n+7), so:

2(2n+1)+5n+7

We add all the numbers together, and all the variables

5n+2(2n+1)+7

We multiply parentheses

5n+4n+2+7

We add all the numbers together, and all the variables

9n+9

Back to the equation:

-(9n+9)



We get rid of parentheses

4n-9n-9-2=0

We add all the numbers together, and all the variables

-5n-11=0

We move all terms containing n to the left, all other terms to the right

-5n=11

n=11/-5

n=-2+1/5

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