n+1=4(n+8)

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Solution for n+1=4(n+8) equation: 



n+1=4(n+8)

We move all terms to the left:

n+1-(4(n+8))=0



We calculate terms in parentheses: -(4(n+8)), so:

4(n+8)

We multiply parentheses

4n+32

Back to the equation:

-(4n+32)



We get rid of parentheses

n-4n-32+1=0

We add all the numbers together, and all the variables

-3n-31=0

We move all terms containing n to the left, all other terms to the right

-3n=31

n=31/-3

n=-10+1/3

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