(4a+12)/10=3(a+1)/6

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Solution for (4a+12)/10=3(a+1)/6 equation: 



(4a+12)/10=3(a+1)/6

We move all terms to the left:

(4a+12)/10-(3(a+1)/6)=0

We calculate fractions


4a/()+(-(3(a+1)*10)/()=0



We calculate terms in parentheses: +(-(3(a+1)*10)/(), so:

-(3(a+1)*10)/(

We multiply all the terms by the denominator


-(3(a+1)*10)



We calculate terms in parentheses: -(3(a+1)*10), so:

3(a+1)*10

We multiply parentheses

30a+30

Back to the equation:

-(30a+30)



We get rid of parentheses

-30a-30

Back to the equation:

+(-30a-30)



We get rid of parentheses

4a/()-30a-30=0

We multiply all the terms by the denominator


4a-30a*()-30*()=0

We add all the numbers together, and all the variables

4a-30a*()=0

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