n+(n+2)=3(n+4+7)

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Solution for n+(n+2)=3(n+4+7) equation: 



n+(n+2)=3(n+4+7)

We move all terms to the left:

n+(n+2)-(3(n+4+7))=0

We add all the numbers together, and all the variables

n+(n+2)-(3(n+11))=0

We get rid of parentheses

n+n-(3(n+11))+2=0



We calculate terms in parentheses: -(3(n+11)), so:

3(n+11)

We multiply parentheses

3n+33

Back to the equation:

-(3n+33)



We add all the numbers together, and all the variables

2n-(3n+33)+2=0

We get rid of parentheses

2n-3n-33+2=0

We add all the numbers together, and all the variables

-1n-31=0

We move all terms containing n to the left, all other terms to the right

-n=31

n=31/-1

n=-31

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