n+(n+.6)=2n+(n+.1)

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Solution for n+(n+.6)=2n+(n+.1) equation: 



n+(n+.6)=2n+(n+.1)

We move all terms to the left:

n+(n+.6)-(2n+(n+.1))=0

We add all the numbers together, and all the variables

n+(n+0.6)-(2n+(n+0.1))=0

We get rid of parentheses

n+n-(2n+(n+0.1))+0.6=0



We calculate terms in parentheses: -(2n+(n+0.1)), so:

2n+(n+0.1)

We get rid of parentheses

2n+n+0.1

We add all the numbers together, and all the variables

3n+0.1

Back to the equation:

-(3n+0.1)



We add all the numbers together, and all the variables

2n-(3n+0.1)+0.6=0

We get rid of parentheses

2n-3n-0.1+0.6=0

We add all the numbers together, and all the variables

-1n+0.5=0

We move all terms containing n to the left, all other terms to the right

-n=-0.5

n=-0.5/-1

n=0.5/1

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