2(2n+.06)=2(3n+.1)

Solution for 2(2n+.06)=2(3n+.1) equation:

2(2n+.06)=2(3n+.1)

We move all terms to the left:

2(2n+.06)-(2(3n+.1))=0

We add all the numbers together, and all the variables

2(2n+0.06)-(2(3n+0.1))=0

We multiply parentheses

4n-(2(3n+0.1))+0.12=0


We calculate terms in parentheses: -(2(3n+0.1)), so:

2(3n+0.1)

We multiply parentheses

6n+0.2

Back to the equation:

-(6n+0.2)


We get rid of parentheses

4n-6n-0.2+0.12=0

We add all the numbers together, and all the variables

-2n-0.08=0

We move all terms containing n to the left, all other terms to the right

-2n=0.08

n=0.08/-2

n=-0.08/2