n(n-1)/2=120

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Solution for n(n-1)/2=120 equation:



n(n-1)/2=120
We move all terms to the left:
n(n-1)/2-(120)=0
We multiply all the terms by the denominator
n(n-1)-120*2=0
We add all the numbers together, and all the variables
n(n-1)-240=0
We multiply parentheses
n^2-1n-240=0
a = 1; b = -1; c = -240;
Δ = b2-4ac
Δ = -12-4·1·(-240)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-31}{2*1}=\frac{-30}{2} =-15 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+31}{2*1}=\frac{32}{2} =16 $

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