0.20(y-4)+0.02y=0.12y-0.6

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Solution for 0.20(y-4)+0.02y=0.12y-0.6 equation: 



0.20(y-4)+0.02y=0.12y-0.6

We move all terms to the left:

0.20(y-4)+0.02y-(0.12y-0.6)=0

We add all the numbers together, and all the variables

0.02y+0.20(y-4)-(0.12y-0.6)=0

We multiply parentheses

0.02y+0.2y-(0.12y-0.6)-0.8=0

We get rid of parentheses

0.02y+0.2y-0.12y+0.6-0.8=0

We add all the numbers together, and all the variables

0.1y-0.2=0

We move all terms containing y to the left, all other terms to the right

0.1y=0.2

y=0.2/0.1

y=2

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