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n(8n+13)=-3
We move all terms to the left:
n(8n+13)-(-3)=0
We add all the numbers together, and all the variables
n(8n+13)+3=0
We multiply parentheses
8n^2+13n+3=0
a = 8; b = 13; c = +3;
Δ = b2-4ac
Δ = 132-4·8·3
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{73}}{2*8}=\frac{-13-\sqrt{73}}{16} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{73}}{2*8}=\frac{-13+\sqrt{73}}{16} $
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