4(-8+1)+2b=3(2b-1)

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Solution for 4(-8+1)+2b=3(2b-1) equation: 



4(-8+1)+2b=3(2b-1)

We move all terms to the left:

4(-8+1)+2b-(3(2b-1))=0

We add all the numbers together, and all the variables

2b-(3(2b-1))+4(-7)=0

We add all the numbers together, and all the variables

2b-(3(2b-1))-28=0



We calculate terms in parentheses: -(3(2b-1)), so:

3(2b-1)

We multiply parentheses

6b-3

Back to the equation:

-(6b-3)



We get rid of parentheses

2b-6b+3-28=0

We add all the numbers together, and all the variables

-4b-25=0

We move all terms containing b to the left, all other terms to the right

-4b=25

b=25/-4

b=-6+1/4

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