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m=6/m+9
We move all terms to the left:
m-(6/m+9)=0
Domain of the equation: m+9)!=0We get rid of parentheses
m∈R
m-6/m-9=0
We multiply all the terms by the denominator
m*m-9*m-6=0
We add all the numbers together, and all the variables
-9m+m*m-6=0
Wy multiply elements
m^2-9m-6=0
a = 1; b = -9; c = -6;
Δ = b2-4ac
Δ = -92-4·1·(-6)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{105}}{2*1}=\frac{9-\sqrt{105}}{2} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{105}}{2*1}=\frac{9+\sqrt{105}}{2} $
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