7*(2a+1)+(3a+2)=20*a-3*(a-3)

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Solution for 7*(2a+1)+(3a+2)=20*a-3*(a-3) equation: 



7(2a+1)+(3a+2)=20a-3(a-3)

We move all terms to the left:

7(2a+1)+(3a+2)-(20a-3(a-3))=0

We multiply parentheses

14a+(3a+2)-(20a-3(a-3))+7=0

We get rid of parentheses

14a+3a-(20a-3(a-3))+2+7=0



We calculate terms in parentheses: -(20a-3(a-3)), so:

20a-3(a-3)

We multiply parentheses

20a-3a+9

We add all the numbers together, and all the variables

17a+9

Back to the equation:

-(17a+9)



We add all the numbers together, and all the variables

17a-(17a+9)+9=0

We get rid of parentheses

17a-17a-9+9=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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