m2+7m-294=0

Solution for m2+7m-294=0 equation:

m2+7m-294=0

We add all the numbers together, and all the variables

m^2+7m-294=0

a = 1; b = 7; c = -294;
Δ = b2-4ac
Δ = 72-4·1·(-294)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-35}{2*1}=\frac{-42}{2}
=-21
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+35}{2*1}=\frac{28}{2}
=14
$