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9c(c-6)=63
We move all terms to the left:
9c(c-6)-(63)=0
We multiply parentheses
9c^2-54c-63=0
a = 9; b = -54; c = -63;
Δ = b2-4ac
Δ = -542-4·9·(-63)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-72}{2*9}=\frac{-18}{18} =-1 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+72}{2*9}=\frac{126}{18} =7 $
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