m1=80,m2

Solution for m1=80,m2 equation:

m1=80.m^2

We move all terms to the left:

m1-(80.m^2)=0

We add all the numbers together, and all the variables

m-(80.m^2)=0

We get rid of parentheses

-80.m^2+m=0

We add all the numbers together, and all the variables

-80m^2+m=0

a = -80; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-80)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-80}=\frac{-2}{-160}
=1/80
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-80}=\frac{0}{-160}
=0
$