-12x2+8x=-20

Solution for -12x2+8x=-20 equation:

-12x^2+8x=-20

We move all terms to the left:

-12x^2+8x-(-20)=0

We add all the numbers together, and all the variables

-12x^2+8x+20=0

a = -12; b = 8; c = +20;
Δ = b2-4ac
Δ = 82-4·(-12)·20
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-32}{2*-12}=\frac{-40}{-24}
=1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+32}{2*-12}=\frac{24}{-24}
=-1
$